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SQL Agent Date and Time Handling
SQL Agent uses two ways to represent date and time information. In some cases it uses the SQL Server datatime data type, but in most occasions it uses two integers to represent the date and time separately. The format of the date and time integers are very straight forward, the date is formatted as YYYYMMDD and the time is formatted as HHMMSS. Everywhere where schedule information is represented the date and time are stored using integers. The problem is that you need to convert the integer representation to a datetime, before you can leverage the existing datetime manipulation functions in SQL Server. This article provides helper functions to convert between the two representations. In total there are five user defined functions.
Below follows the source code for the five user defined functions: create function [dbo].[fn_AgentDate2DateTime] (@agentdate int)returns datetime as begin declare @date datetime, @year int, @month int, @day int, @datestr nvarchar(40) select @year = (@agentdate / 10000) select @month = (@agentdate - (@year * 10000)) / 100 select @day = (@agentdate - (@year * 10000) - (@month * 100)) select @datestr = convert(nvarchar(4), @year) + N'-' + convert(nvarchar(2), @month) + N'-' + convert(nvarchar(4), @day) select @date = convert(datetime, @datestr) return @date end go -- example select [dbo].[fn_AgentDate2DateTime](20020430) go create function [dbo].[fn_AgentTime2DateTime](@agenttime int) returns datetime as begin declare @date datetime, @hour int, @min int, @sec int, @datestr nvarchar(40) select @hour = (@agenttime / 10000) select @min = (@agenttime - (@hour * 10000)) / 100 select @sec = (@agenttime - (@hour * 10000) - (@min * 100)) select @datestr = replace(convert(nvarchar(2), @hour) + N':' + convert(nvarchar(2), @min) + N':' + convert(nvarchar(2), @sec), ' ', '0') select @date = convert(datetime, @datestr) return @date end go -- example select [dbo].[fn_AgentTime2DateTime] (110015) go create function [dbo].[fn_AgentDateTime2DateTime] (@agentdate int, @agenttime int) returns datetime as begin declare @date datetime, @year int, @month int, @day int, @hour int, @min int, @sec int, @datestr nvarchar(40) select @year = (@agentdate / 10000) select @month = (@agentdate - (@year * 10000)) / 100 select @day = (@agentdate - (@year * 10000) - (@month * 100)) select @hour = (@agenttime / 10000) select @min = (@agenttime - (@hour * 10000)) / 100 select @sec = (@agenttime - (@hour * 10000) - (@min * 100)) select @datestr = convert(nvarchar(4), @year) + N'-' + convert(nvarchar(2), @month) + N'-' + convert(nvarchar(4), @day) + N' ' + replace(convert(nchar(2), @hour) + N':' + convert(nchar(2), @min) + N':' + convert(nchar(2), @sec), ' ', '0') select @date = convert(datetime, @datestr) return @date end go -- example select [dbo].[fn_AgentDateTime2DateTime] (20020222, 110015) go create function [dbo].[fn_DateTime2AgentDate] (@date datetime) returns int as begin declare @dateint int select @dateint = (datepart(year, @date) * 10000) + (datepart(month, @date) * 100) + (datepart(day, @date)) return @dateint end go -- example select [dbo].[fn_DateTime2AgentDate] (getdate()) go create function [dbo].[fn_DateTime2AgentTime] (@date datetime) returns int as begin declare @timeint int select @timeint = (datepart(hour, @date) * 10000) + (datepart(minute, @date) * 100) + (datepart(second, @date)) return @timeint end go -- example select [dbo].[fn_DateTime2AgentTime] (getdate()) go Download agent_datetime_functions.sql The following tables use the alternative date and time representation:
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